Bending Moment Problem: Finding the Moment & Shear Force

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SUMMARY

The discussion focuses on calculating the bending moment and shear force for a simply supported beam with a solid square cross-section of 200mm x 200mm and a length of 30m, subjected to a uniform distributed load (UDL) of 120kN between 8m and 20m from the left side. The reactions at the supports were calculated as r1=214kN and r2=206kN. The correct approach involves taking moments about the supports and ensuring that the sum of the reactions equals the total load, including the beam's weight of 10kN/m. For shear force calculations, the sum of external forces on either side of a section must be considered.

PREREQUISITES
  • Understanding of static equilibrium principles in structural analysis
  • Familiarity with bending moment and shear force diagrams
  • Knowledge of simply supported beam mechanics
  • Basic calculations involving uniform distributed loads (UDL)
NEXT STEPS
  • Study the method for calculating bending moments in simply supported beams
  • Learn how to construct shear force and bending moment diagrams
  • Explore the principles outlined in "Strength of Materials" by Stephen Timoshenko
  • Review the calculations for reactions in beams with various loading conditions
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Structural engineers, civil engineering students, and anyone involved in analyzing beam mechanics and load distributions in construction projects.

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The question.

A beam with a solid square cross section of 200mm x 200mm with a length of 30m is simply supported at both ends. Weight of beam = 10kn/m. The beam has a UDL of 120KN which lies between 8m and 20m from the left hand side.

I am fairly new to this so please bear with me. I have found moments for r1 and r2 as follows.

r1=214kn r2=206kn

I need to find the bending moment and shear force however can't remember the method for this. Could anyone just run me through the rough calculations without giving me the answer. Many Thanks.
 
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If the beam is simply supported at each end, and has a uniform section and weight, and the load is uniform, I would expect the reactions to be equal at each end.
The total of the reactions should add up to the total load, includeing weight.
Your attempt at the solution does not seem to satisfy the above criteria.

To calculate the reactions, you take moments about points 1 and 2 in turn, which leaves you with an equation with one unknown at a time (r2 and r1). If they come out not equal for a symmetrical beam with symmetrical load, you understand that there is a little problem. Another check is to add up r1 and r2, the sum of which should equal the total loads including self-weight.

The shear force at a particular section is relatively easy to calculate, namely it is the sum of all external forces on the left (or on the right, since they should be equal but opposite in direction) of the section. The beam's cross section is resisting this difference in forces.

If you have a chance to rework on your calculations and post the details of the calculations, I would be more than glad to help you check your calculations.

If you have a chance to go to the university library, look up some books on Strength of Materials. They should all explain the subject in much more details than we can do at a forum.
Some classic titles are :

Strength of materials by Stephen Timoshenko
https://www.amazon.com/dp/0898746213/?tag=pfamazon01-20
Strength of materials by Den Hartog
https://www.amazon.com/dp/0486607550/?tag=pfamazon01-20
 

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