Problems about calculating acceleration,velocity

  • Thread starter Thread starter acelya
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around calculating acceleration and velocity for a car moving along a curvilinear road, with specific equations for acceleration provided. Participants also explore a separate problem involving a particle with an initial velocity and deceleration.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between tangential acceleration and how to derive velocity and distance from it. There are questions about the initial conditions needed to solve the problems, particularly regarding the position and velocity of the car and particle.

Discussion Status

There is an ongoing exploration of how to apply calculus to find velocity and distance given the tangential acceleration. Some participants suggest using integrals, while others express uncertainty about initial conditions and constants involved in the equations.

Contextual Notes

Participants note the lack of explicit initial conditions in the problem statements, which complicates their ability to determine constants in their equations. There is also mention of a specific parameter related to the curvilinear path that needs to be considered.

acelya
Messages
5
Reaction score
0

Homework Statement



A car, as shown in the figure, is going in a curvilinear road. The size of the car will be neglected.

Homework Equations



Its acceleration is a = 0.5*e^t m/s^2.

The Attempt at a Solution



If it goes 18 meters on its way, then calculate its velocity and acceleration.

I have one more question. A particle is making linear action. Its velocity in the origin is 4 m/s. If particle is slowing down with acceleration a = -3/2*v^1/2 m/s^2, calculate the elapse time and its taking way until it stops(v=0).

Hope I could explain my questions clearly. How can I calculate them? Please help me.
 

Attachments

Physics news on Phys.org
acelya said:
Its acceleration is a = 0.5*e^t m/s^2.
I assume that is the tangential acceleration.

If it goes 18 meters on its way, then calculate its velocity and acceleration.
Given acceleration, how do you find velocity and distance?
 
Yes, that is the tangential acceleration.

I don't know how can I find their values, bacause it is going on a curvilinear road and there is a p value (you can see in the figure) p=30m. I must use this value of p.
 
acelya said:
Yes, that is the tangential acceleration.

I don't know how can I find their values, bacause it is going on a curvilinear road and there is a p value (you can see in the figure) p=30m. I must use this value of p.
You'll use the radius to find the centripetal component of the acceleration.

But first things first. How can you find the velocity and distance, given the tangential acceleration? Hint: Calculus.
 
I must use the integral. Distance velocity v=0.5e^t+c1 and distance x=0.5e^t+c1t+c2 (c1,c2 constant values). But then, it is going 18 meters on the road.
 
acelya said:
I must use the integral. Distance velocity v=0.5e^t+c1 and distance x=0.5e^t+c1t+c2 (c1,c2 constant values). But then, it is going 18 meters on the road.
Good. What are c1 and c2? (Those depend on the initial conditions.)
 
But I don't know where the car was on the road firstly. If at t=0, it was in origin, then c1=-0,5 , c2=0. But, this question don't tell us it was in the origin at first.
 
acelya said:
But I don't know where the car was on the road firstly. If at t=0, it was in origin, then c1=-0,5 , c2=0. But, this question don't tell us it was in the origin at first.
You have to know the initial velocity and position or be able to make reasonable assumptions. That it starts from rest and at x = 0 seems reasonable. How did you get c2 = 0?
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
929
Replies
57
Views
3K
Replies
3
Views
2K