A Cutnell and Johnson Physics question illustrates a rocket launch: A rocket is fired at a speed of 97.0 m/s from ground level, at an angle of 53.0 ° above the horizontal. The rocket is fired toward an 27.0-m high wall, which is located 24.0 m away. The rocket attains its launch speed in a negligibly short period of time, after which its engines shut down and the rocket coasts. By how much does the rocket clear the top of the wall? My Calculations: Vo = 97.0 m/s Theta = 53 degrees x = 24 m y = 27 m Let H illustrate the height of the rocket at point x on the axis. t = ? a = -9.80 m/s ^2 Vo sin 53 = Voy = 77.46 Vo cos 53 = Vox = 58.37 x = Vox(t) t = x/Vox = 24/58.37 = .411 s H = Voy(t) + .5 a(t^2) Plug and Chug H = 77.46(.411) + .5(-9.80)(.411^2) = 31 m Distance Rocket clears wall = 31m-27m = 4.00 m <-----Incorrect. Is there a problem with my calculations that I am not understanding?