Projectile Motion Analysis: Golf Ball Speed, Distance, and Height

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The discussion focuses on analyzing the projectile motion of a golf ball struck at ground level, with specific attention to its speed over time. The speed graph indicates that the ball reaches a maximum speed of 32.93 m/s and a minimum speed of 18.92 m/s at defined time intervals. Participants are tasked with calculating the horizontal distance traveled before the ball returns to the ground and determining the maximum height achieved. There is uncertainty regarding the appropriate equations to use, particularly due to the absence of an angle (theta) in the provided information. The conversation emphasizes extracting values from the graph to aid in solving these projectile motion problems.
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Homework Statement


A golf ball is struck at ground level. The speed of the golf ball as a function of time is shown in the figure below, where t = 0 at the instant the ball is struck. The graph is marked in increments of 0.55 s along the time axis, and vmin = 18.92 m/s and vmax = 32.93 m/s. (Values in figure do not necessarily match values in problem).

This graph is then provided:
UiVSZ.gif


a) How far does the golf ball travel horizontally before returning to ground level?
b) What is the maximum height above the ground level attained by the ball?

Homework Equations


I'm not sure, because each applicable equation I find has the need for a theta in it.

The Attempt at a Solution


I can't even find a working equation.

Thanks a lot!
 
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What values can you pick out from the given information? List them.
(Hint: some may require looking for points of interest on the graph and measuring/deducing values).
 
gneill said:
What values can you pick out from the given information? List them.
(Hint: some may require looking for points of interest on the graph and measuring/deducing values).

The points that I am able to get from the graph are:
t(0)= 32.93 m/s
t(2.75)= 18.92 m/s
t(5.5)= 32.93 m/s
 
You also know the total time the ball is in flight.

Plus what does the value of Vmin=18.92 m/s tell you about the vertical and/or horizontal velocity at that time?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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