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Homework Help: Projectile Motion (Baseball Question)

  1. Feb 15, 2010 #1
    So I've been having trouble with a problem dealing with projectile motion.

    Here's the question:

    How much will a ball drop if a pitcher throws the ball horizontally with a speed of 36.5 m/s, from 18m away? (Assuming no spin has been imparted on the ball.)

    I'm not sure where to even start at and am really stumped.
     
    Last edited: Feb 15, 2010
  2. jcsd
  3. Feb 15, 2010 #2

    madmike159

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    Gold Member

    You need to use the SUVAT equations (google them). For projectile motion question you can break it into 2 parts horizontal and vertical. The horizontal time needs to be calculated using v=s/t, then you need to work out how much gravity pulls it down in that time. g = 9.81ms^-2.
     
  4. Feb 15, 2010 #3
    Awesome I figured it out. Thanks.

    v=d/t
    36.5=18/t
    Divide 18 by 36.5= 0.493

    (v1+v2)/2= (0+4.831)/2= 2.416

    Here's how I got the v1 and v2:
    v1= 0
    v2= g x t
    v2= 9.8m/s x 0.493= 4.831

    Finally:

    d=v x t
    d=2.416 x 0.493
    d= 1.191 m
     
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