Projectile motion equation help

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 3K views
Jeffeff
Messages
1
Reaction score
0

Homework Statement


Using these two equations of (1) Dx=(Vox)t and (2) Dy= -(1/2)gt^2 I have to find an expression of Dy as a function of Dx

Vox = initial component of velocity at time =0
Dx = Distance traveled horizontally
Dy= Distance traveled vertically upward

Homework Equations


Dx=(Vox)t and Dy= -(1/2)gt^2


The Attempt at a Solution


I rearranged equation (1) to get time; t=Dx/Vox and used this in equation (2) to substitute for t and coming up with the equation Dy = -g(Dx^2/Vox^2/2. I'm not quite sure I did this right any help would be appreciated.

Thanks in advance!
 
Physics news on Phys.org
Jeffeff said:

Homework Statement


Using these two equations of (1) Dx=(Vox)t and (2) Dy= -(1/2)gt^2 I have to find an expression of Dy as a function of Dx

Vox = initial component of velocity at time =0
Dx = Distance traveled horizontally
Dy= Distance traveled vertically upward

Homework Equations


Dx=(Vox)t and Dy= -(1/2)gt^2

The Attempt at a Solution


I rearranged equation (1) to get time; t=Dx/Vox and used this in equation (2) to substitute for t and coming up with the equation Dy = -g(Dx^2/Vox^2/2. I'm not quite sure I did this right any help would be appreciated.

Thanks in advance!
Hello Jeffeff. Welcome to PF !

You have unbalanced parentheses. Assuming you mean that Dy = -g(Dx2/V0x2)/2, that's correct.
 
Last edited: