Projectile Motion from a cliff with no information.

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stridle
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Homework Statement


The range of a cannonball fired horizontally from a cliff is equal to the height of the cliff. What is the direction of the velocity vector of the projectile as it strikes the ground? (ignore air resistance)


Homework Equations



I attempted setting delta y = delta x, but had not luck.

The Attempt at a Solution



The apparent solution is 63.4 degrees below the horizon.
 
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delta x= v[initial]*t and delta y=0.5*g*t*t as velocity is zero along y-axis initially.
What do you get when you equate the two?
 
I get inital velocity = .5*g*t. I found that solution earlier but I do not understand how they get an angle from that information?
 
This velocity of yours is along which axis?
 
I honestly am very confused at this point.
 
I figured it out thanks for the help.