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Projectile Motion from a cliff with no information.

  1. Feb 13, 2010 #1
    1. The problem statement, all variables and given/known data
    The range of a cannonball fired horizontally from a cliff is equal to the height of the cliff. What is the direction of the velocity vector of the projectile as it strikes the ground? (ignore air resistance)


    2. Relevant equations

    I attempted setting delta y = delta x, but had not luck.

    3. The attempt at a solution

    The apparent solution is 63.4 degrees below the horizon.
     
  2. jcsd
  3. Feb 13, 2010 #2
    delta x= v[initial]*t and delta y=0.5*g*t*t as velocity is zero along y-axis initially.
    What do you get when you equate the two?
     
  4. Feb 13, 2010 #3
    I get inital velocity = .5*g*t. I found that solution earlier but I do not understand how they get an angle from that information?
     
  5. Feb 13, 2010 #4
    This velocity of yours is along which axis?
     
  6. Feb 14, 2010 #5
    I honestly am very confused at this point.
     
  7. Feb 14, 2010 #6
    I figured it out thanks for the help.
     
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