Projectile Motion- How to Calculate Displacement

Click For Summary
SUMMARY

The discussion focuses on calculating the displacement of a projectile launched at various angles, given its initial velocity and the acceleration due to gravity (9.8 m/s²). Participants clarify that the horizontal acceleration is zero when neglecting air resistance, and emphasize the importance of determining the time the projectile is in the air. Key equations discussed include horizontal displacement = initial horizontal velocity * time and the vertical motion equations, which are influenced by gravity. The conversation concludes with the acknowledgment that air resistance complicates calculations, requiring specific formulas for accurate modeling.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations (e.g., S=ut+1/2at²)
  • Basic knowledge of vector components (horizontal and vertical velocities)
  • Concept of gravitational acceleration (9.8 m/s²)
NEXT STEPS
  • Learn to apply kinematic equations to both horizontal and vertical components of projectile motion
  • Research how to calculate the time of flight for projectiles
  • Explore the effects of air resistance on projectile motion and relevant formulas
  • Study the decomposition of initial velocity into horizontal and vertical components
USEFUL FOR

Students studying physics, educators teaching projectile motion, and anyone interested in understanding the dynamics of objects in motion under gravity.

  • #31
Yes, since a bullet is being shot out of a gun.
 
Physics news on Phys.org
  • #32
Jai said:
Yes, since a bullet is being shot out of a gun.

If the velocity is zero, then it's not being shot out of a gun, it's just sitting in a gun.


When I said "initial velocity" in my other post I meant "initial velocity" after it's been shot
 
  • Like
Likes   Reactions: 1 person
  • #33
Nathanael said:
If the velocity is zero, then it's not being shot out of a gun, it's just sitting in a gun.

Yes, however I mean that for my original question, so now the approach may be different?
 
  • #34
Jai said:
Thanks for the reply. Yes I did consider that and try using the equations t=s/v, V=u+at, S=ut+1/2at^2 and V^2=u^2+2as but none of these seemed to work. They are the only equations I have been taught involving time.
Those equations are good. They are what you use. You just need to apply them separately to the horizontal component of initial velocity and to the vertical component of initial velocity. Vertical motion is influenced by gravity, horizontal motion is influenced by only air resistance (if present).

If a projectile has no initial horizontal velocity component then its motion will just be a vertical rise, then fall back to where it started.
 
  • Like
Likes   Reactions: 1 person
  • #35
NascentOxygen said:
Those equations are good. They are what you use. You just need to apply them separately to the horizontal component of initial velocity and to the vertical component of initial velocity. Vertical motion is influenced by gravity, horizontal motion is influenced by only air resistance (if present).

If a projectile has no initial horizontal velocity component then its motion will just be a vertical rise, then fall back to where it started.

Thanks, I applied them separately and managed to get what I need. While you are here do you know some sort of formula that could be used to take into account air resistance? My teacher said that we need to mention the formula but not calculate it because it is too complicated to get the data for.
 

Similar threads

Replies
40
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
3K
  • · Replies 15 ·
Replies
15
Views
26K