Jai
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Yes, since a bullet is being shot out of a gun.
The discussion focuses on calculating the displacement of a projectile launched at various angles, given its initial velocity and the acceleration due to gravity (9.8 m/s²). Participants clarify that the horizontal acceleration is zero when neglecting air resistance, and emphasize the importance of determining the time the projectile is in the air. Key equations discussed include horizontal displacement = initial horizontal velocity * time and the vertical motion equations, which are influenced by gravity. The conversation concludes with the acknowledgment that air resistance complicates calculations, requiring specific formulas for accurate modeling.
PREREQUISITESStudents studying physics, educators teaching projectile motion, and anyone interested in understanding the dynamics of objects in motion under gravity.
Jai said:Yes, since a bullet is being shot out of a gun.
Nathanael said:If the velocity is zero, then it's not being shot out of a gun, it's just sitting in a gun.
Those equations are good. They are what you use. You just need to apply them separately to the horizontal component of initial velocity and to the vertical component of initial velocity. Vertical motion is influenced by gravity, horizontal motion is influenced by only air resistance (if present).Jai said:Thanks for the reply. Yes I did consider that and try using the equations t=s/v, V=u+at, S=ut+1/2at^2 and V^2=u^2+2as but none of these seemed to work. They are the only equations I have been taught involving time.
NascentOxygen said:Those equations are good. They are what you use. You just need to apply them separately to the horizontal component of initial velocity and to the vertical component of initial velocity. Vertical motion is influenced by gravity, horizontal motion is influenced by only air resistance (if present).
If a projectile has no initial horizontal velocity component then its motion will just be a vertical rise, then fall back to where it started.