- #1

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Can someone please explain how to approach this problem.

- Thread starter dontcare
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- #1

- 12

- 0

Can someone please explain how to approach this problem.

- #2

tony873004

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Start by figuring out its velocity after 3 seconds of accelerating.

- #3

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This is what i have so far.

Part a:

s = vot + (.5)at^2

s = 100m/s(3s) + .5(30m/s/s)(3s)^2 = 435 m

y1 = s(sin 53) = 347 m

y2= [100(sin53)^2 / 2(9.8)] = 325 m

ytotal = 347 + 325 = 672 m

The rest of the problem will be solved incorrectly. But here is what i would have done if the previous answer was correct.

Part b:

t(total) = t1 + t2

t1= 3s

y= vo(sin53)t - .5*g*(t^2)

solve for time using quadratic eqn.

Part c

x1 = v0t + .5(a)t^2 = 262m

x2 = s(cos 53) = 435m

xtotal = 435 + 262 = 697 m

- #4

tony873004

Science Advisor

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