Projectile Motion Neglecting air resistance

In summary, the conversation discusses the motion of a ball thrown straight up with a speed of 20 m/s, neglecting air resistance. The question is how far the ball will have moved when it is caught. The poster also asks if there are any relevant equations that can be used to solve the problem.
  • #1
JenniferT
2
0

Homework Statement


Neglecting air resistance, if you throw a ball straight up with a speed of 20 m/s, how far will it be moving when you catch it?

Homework Equations


None

The Attempt at a Solution

 
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  • #2
Do you mean how fast will it be moving when you catch it?

Are you sure there are no relevant equations to help you solve this problem? Did you give up while writing this post?
 
  • #3
SteamKing said:
Do you mean how fast will it be moving when you catch it?

Are you sure there are no relevant equations to help you solve this problem? Did you give up while writing this post?
I did mean how fast. Please excuse my typing error.
 
  • #4
Still, the larger, unresolved issue is, are you sure there are no relevant equations you can apply to analyzing this problem?
 
  • #5

The distance the ball will travel while in the air can be calculated using the equation d = v*t, where d is the distance, v is the initial velocity, and t is the time. In this case, the ball is thrown straight up with a velocity of 20 m/s, so the initial velocity is positive. When the ball reaches its highest point, it will have a velocity of 0 m/s, and then it will begin to fall back down with a negative velocity. However, since we are neglecting air resistance, the ball will have the same velocity on its way down as it did on its way up. Therefore, the total time the ball is in the air can be calculated by dividing the initial velocity by the acceleration due to gravity, which is approximately 9.8 m/s^2. So, t = 20 m/s / 9.8 m/s^2 = 2.04 seconds. Plugging this value into the distance equation, we get d = 20 m/s * 2.04 s = 40.8 m. Therefore, the ball will travel approximately 40.8 meters before it is caught.
 

What is projectile motion neglecting air resistance?

Projectile motion neglecting air resistance is a type of motion that occurs when an object is thrown or launched into the air without any external forces acting on it, such as air resistance. This type of motion is often studied in physics and can help us understand the behavior of objects in motion.

How is the motion of a projectile affected by air resistance?

Air resistance can affect the motion of a projectile by slowing it down and changing its trajectory. This is because air resistance acts as a force that opposes the motion of the projectile, causing it to lose energy and change direction.

What is the formula for calculating the horizontal distance of a projectile?

The formula for calculating the horizontal distance of a projectile is d = v*cos(θ)*t, where d is the distance, v is the initial velocity, θ is the launch angle, and t is the time in flight. This formula assumes that air resistance is negligible.

What is the maximum height of a projectile?

The maximum height of a projectile can be calculated using the formula h = (v*sin(θ))^2 / (2*g), where h is the maximum height, v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity. This formula also assumes that air resistance is negligible.

How does the angle of launch affect the motion of a projectile?

The angle of launch can greatly affect the motion of a projectile. Changing the angle can change the distance and height the projectile travels, as well as its overall trajectory. A higher angle will result in a longer flight time and a lower angle will result in a shorter flight time.

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