Projectile motion of a flicked ball

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Discussion Overview

The discussion revolves around solving a projectile motion problem involving a ball flicked from a tabletop. Participants explore the calculations necessary to determine the horizontal distance the ball travels when launched horizontally and at a 30-degree angle. The scope includes mathematical reasoning and problem-solving strategies under exam conditions where calculators are not permitted.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant expresses difficulty in solving the problem without using quadratics and requests assistance.
  • Another participant suggests using a specific website for guidance on horizontal launch calculations.
  • A participant attempts to solve part (b) but arrives at an incorrect answer, questioning their approach and calculations.
  • There is a suggestion to use the quadratic formula to find time in the vertical motion equation.
  • Some participants inquire about alternative methods to solve the problem without the quadratic formula, emphasizing the challenge of not using a calculator.
  • Participants discuss breaking down the problem into steps, such as finding the time to the highest point and the distance fallen from there.
  • Questions arise regarding the feasibility of performing calculations without a calculator, particularly for determining initial velocities in different directions.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method to solve the problem without a calculator. Multiple approaches and uncertainties about the calculations are present throughout the discussion.

Contextual Notes

Participants express limitations due to the exam conditions, specifically the prohibition of calculators, which affects their ability to perform certain calculations easily. There is also uncertainty regarding the correct application of equations and methods for solving the projectile motion problem.

lulusmith
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Really can't figure this out by dividing x and y. The only way i can do it is with equations that use quadratics and I can't do that in my head for a test were I'm not allowed a calculator.Please help, Thank you!

You flick a ball from a tabletop, so that the ball lands on the floor 1.20 m below. The ball's initial speed is 2.40 m/s. Use g = 9.80 m/s2.

(a) If the ball is launched off the table horizontally, what is the horizontal distance between the launch point and the point where the ball hits the floor?

(b) If the ball is launched off the table at a 30 degree angle above the horizontal, what is the horizontal distance between the launch point and the point where the ball hits the floor?
 
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So I looked at the site and this is what I did:
ok so I got part a.

I didn't get part b.
What I did was solve for t first:
Y=Yo+ VoyT + aT^2/2
Y= 1.2m + 1.2(got this from 2.4sin30)t + (-9.8)(t^2)/2
t+t^2 = -1.2x2/9.8
-1.24t = 1
t= 0.80

Then I used t to solve for ax:

Vx=Vox+at;
0= 2.08 (from 2.4cos30) + a(0.8);
a= 2.6

Then I used this to solve for x (AKA range):
x = Xo + VoxT +at^2/2
x= 2.08(0.8)+ 2.6(0.8^2)/2;
x= 2.50

But it was wrong, so what did I do wrong?
 
for the first part where you found t, you should use the quadratic formula to solve the expression y = ...
 
Isn't there an easier way to solve it w/o using the quadratic formula?
(I'm not allowed to use a calculator during the exam)
 
lulusmith said:
Isn't there an easier way to solve it w/o using the quadratic formula?
(I'm not allowed to use a calculator during the exam)
You can solve it in steps:
- Find the time it takes to get to the highest point of its motion
- Find the distance of the highest point above the table (and the floor)
- Find the time it takes to fall to the floor from the highest point

Seems like quite a handicap not to use a calculator.
 
Could you show me how to actually do the problem (e.g: the equation I would have to use)?
 
lulusmith said:
Could you show me how to actually do the problem (e.g: the equation I would have to use)?
I'll give you the first step: v = v0 + at

What's the vertical speed at the highest point?
 
are you sure you're not allowed a calculator? That would make calculating the initial velocity in the x and y direction a bit difficult, unless they want you to leave it as 2.4sin30 or whatever
 

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