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Mdhiggenz
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Homework Statement
A hiker throws a stone from the upper edge of a vertical cliff. The stone ' s initial velocity is 25.0 m/s directed at 40.0 degrees with the face of the cliff, as shown in Fig. 3.1. The stone hits the ground 3.75 s after being thrown and feels no appreciable air resistance as it falls. the height of the cliff is closest to
Here is the link to the picture: http://img10.imageshack.us/img10/8058/58525486.jpg
Homework Equations
The Attempt at a Solution
So what I first did was break the velocity into its vertical and horizontal components,
25.0sin40=16.06m/s(y0)
25.0cos40=19.15m/s(x0)
We know the time it takes to hit the gound is 3.75 seconds
I got its Vy( final velocity) by using the following equation vy=vosina-gt
vy=16.0sin40-9.8(3.75s)
=-26.46m/s
Here is where I start getting lost, I wanted to solve for deltay using the following formula;
vf^2=vi^2+2aDeltay
(-24.46)^2-(16.06)^2/2(-9.8).. and I got some funky answer, the answer to the problem is 141.
Can someone walk me through how to get that answer, thank you!
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