Projectile motion of tennis ball

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Homework Help Overview

The discussion revolves around a physics problem related to projectile motion, specifically analyzing the trajectory of a tennis ball served at different angles and velocities. The original poster presents a scenario where a tennis player serves a ball at a velocity of 50 m/s at angles of 10° and 5° to the horizontal, with the goal of determining whether the ball can pass over the net.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculations related to the ball's vertical and horizontal motion, questioning the assumptions made about the heights involved (player height and net height). There are inquiries about the nature of the serve (tennis vs. badminton) and how it might affect the trajectory.

Discussion Status

Some participants are engaging with the original poster's calculations, seeking clarification on specific values and the setup of the problem. There is a mix of agreement and further questioning regarding the interpretation of the heights and the implications for the ball's trajectory.

Contextual Notes

Participants are considering the heights of the player and the net, with some suggesting that the vertical distance should be re-evaluated in relation to the net height. There is uncertainty about the exact parameters of the serve and how they influence the calculations.

kisha
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Homework Statement



A tennis player serves in a match.He hits the tennis ball so that it flies off the racket with a velocity of 50m/s at 10° to the horizontal.

Sx=11m
Sy=2.4 - 1.07 = 1.33m
ux=50cos10°
uy=50sin10°
time=?

a)Show that the ball cannot pass over the net.

b)The player serves again.He hits the ball at the same height.The ball flies off at the same speed but it only makes an angle of 5° with the horizontal.

(i)Show that the ball passes over the net this time.
(ii)When does the ball land after the serve?Find its horizontal displacement when it lands.
(iii)Find the velocity at which the ball hits the floor.

Homework Equations



Vy = Uy - gt
Sy=Uy - 1/2gt^2
Sx=Ux(t)
Vx=Ux

The Attempt at a Solution



Time of flight=[PLAIN]http://img600.imageshack.us/img600/5889/29072134.png

vertical distance = h = usinθ(t)-1/2gt^2
=[PLAIN]http://img825.imageshack.us/img825/369/24954548.png
=[PLAIN]http://img202.imageshack.us/img202/5079/78644637.png

Since,
Sy=Sxtanθ

h=[PLAIN]http://img191.imageshack.us/img191/6696/36239012.png

Therefore,the ball passes below the net at a separation of=

[PLAIN]http://img576.imageshack.us/img576/6231/89145724.png

In other words,it is impossible for the ball pass the net.

Can anyone help with this?How to prove the ball cannot pass over the net?
 
Last edited by a moderator:
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can you explain more?
IS THE PLAYER DOING A TENNIS SERVE OR BADMINTON SERVE ,i.e. IS HE SWINGING HAND FROM ABOVE HEAD OR BELOW STOMACH?
 
re 1994Bhaskar:

The player swinging his hand above head:).
 
" Sy=2.4 - 1.07 = 1.33m "

Can you tell me is it 2.4m is the player height and the 1.33m is the net height ?:shy:

If not going wrong! Your distance vertical = h , should be Sy then you can get the answer.:smile:
 
Last edited:
re xiaoB:

Yes:).you're right
 
kisha said:
re xiaoB:

Yes:).you're right

If not going wrong! Your distance vertical = h , should be Sy then you can get the answer.:smile:
 
If not going wrong! You can poof the h =0.7...m is below then the net height.:shy:
 
1994Bhaskar said:
can you explain more?
IS THE PLAYER DOING A TENNIS SERVE OR BADMINTON SERVE ,i.e. IS HE SWINGING HAND FROM ABOVE HEAD OR BELOW STOMACH?

xiaoB said:
If not going wrong! You can poof the h =0.7...m is below then the net height.:shy:

I guess it!thank you for your help:).You get me out of trouble.
 

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