# Projectile Motion problem (is my textbook wrong?)

## Homework Statement

"A slingshot fires a stone horizontally from a tower 32 metres high, and it lands 135 metres from the foot of the tower. What was the speed at which it left the slingshot?"
Verticle Height = 32m
Horizontal Distance = 135m

## The Attempt at a Solution

I first calculated the time the rock is in the air using t=sqrt(2s/g). I got 2.55s which is the same as the textbook. However, the textbook then calculates the velocity of the rock using s/t. They get an answer of 53m/s. However this is where I'm confused: isn't this calculating the average speed of the stone?

Alternatively, I calculated the inital velocity of the stone using s=(Vi)(t) + 0.5(a)(t^2). You know all variables in this equation (s=135m, t = 2.55s, a = 9.8m/s^2) so I just rearranged to find the inital velocity.

I'm a self-taught beginner at Physics who just needs a little help with this question :(

gneill
Mentor

## Homework Statement

"A slingshot fires a stone horizontally from a tower 32 metres high, and it lands 135 metres from the foot of the tower. What was the speed at which it left the slingshot?"
Verticle Height = 32m
Horizontal Distance = 135m

## The Attempt at a Solution

I first calculated the time the rock is in the air using t=sqrt(2s/g). I got 2.55s which is the same as the textbook. However, the textbook then calculates the velocity of the rock using s/t. They get an answer of 53m/s. However this is where I'm confused: isn't this calculating the average speed of the stone?

Alternatively, I calculated the inital velocity of the stone using s=(Vi)(t) + 0.5(a)(t^2). You know all variables in this equation (s=135m, t = 2.55s, a = 9.8m/s^2) so I just rearranged to find the inital velocity.

I'm a self-taught beginner at Physics who just needs a little help with this question :(

In what direction (horizontal or vertical) does the acceleration due to gravity apply? Does the rock change speed in the horizontal direction?

"In what direction (horizontal or vertical) does the acceleration due to gravity apply? Does the rock change speed in the horizontal direction? "

Both? I guess if you're throwing something horizontally wouldn't it slowly fall as a result of the gravitational force? I honestly don't know :( And wouldn't the rock eventually slow down? Or is it because it is constantly going the same horizontal speed and eventually hits the ground because of gravity pushing down on it?

That sounded confusing: Im trying to say that if the rock is constantly going at the same horizontal speed what causes it to fall and stop?

CWatters
Science Advisor
Homework Helper
Gold Member
Gravity accelerates the stone in the vertical direction but there is nothing that would cause it to accelerate in the horizontal direction. So the horizontal component of the stones velocity is constant (ignoring air resistance).

Yes the rock keep on moving in horizontal and vertical motion until it is stopped by the ground.
It's not the average motion but the sum of 2 motions(vectors), vertical and horizontal motion.

This makes much more sense now! Thanks! :)

CWatters
Science Advisor
Homework Helper
Gold Member
There are sereral variants of this question that come up in exams. They typically involve cannon balls being fired up in the air or rolled of the edge of a table of some such. You get to write equations for the horizontal and vertical velocity and are asked to solve them to find some unknown. The first few times you get these problems it may appear as if you don't have enough information to solve the equations but the trick is to look to see what you can get from the start or end conditions. For example if you fire a cannon ball up into the air at an angle there will be a point at which the vertical component of it's velocity falls to zero and it starts to come down again even if the horizontal velocity is a constant 1000mph. Its these extra/end conditions that are usually the key to solving the problem.

Another question: "You drive a car 45 miles north 30° west. How much further west are you?"

I drew it so the angle is 30 degrees with the x axis and then used (cos 30)(45) to find the distance west. My textbook uses cos 60 x 45! :( why am I incorrect?

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