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**Here is the problem :**

A Sniper is lying in a prone position such that the barrel of his rifle is parallel to and 30cm above the ground. The muzzle velocity of his rifle is 800m/s

A target appears at a distance of 1250m with the centre of the target 1.2m above ground level. If the sniper were firing from the prone position, calculate the angle to which the barrel of the rifle should be raised to hit the centre of the target

**Also there is assumed no air resistance.**

The Equations for projectiles are:

*Vx = Ux*

v = u + at

Vy^2 = Uy^2 + 2ay * Δy (ay is -9.8, don't know how to type subscript)

Δx = Ux * t

Δy = Uy * t + a/2 * t^2

v = u + at

Vy^2 = Uy^2 + 2ay * Δy (ay is -9.8, don't know how to type subscript)

Δx = Ux * t

Δy = Uy * t + a/2 * t^2

*I'm in high school and this question is part of my HW btw*

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