Projectile motion equation stuck downwards velocity and angle

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emvizzle
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1. A projectile motion is fired horizontally at 150ms-1 from the top of a 196m high cliff. Calculate its velocity on hitting the ground.



2. Okay so I've already discovered its time of flight t = 6.32s and its range Δx = 948m.
Other figures are Δy= 196m, ay= -9.8ms-1, ux=150ms-1, Vy= 0ms-1, uy= 61.96ms-1




 
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Hey.All your answers are spot on .

The velocity vector is 150i-62j

(rounding 61.96 as 62).

So you have the velocity vector.You can find the magnitude of velocity (which I think the question meant by asking the velocity.Speed would have been a better term)and the angle it makes with the horizontal.