velocityay
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Homework Statement
At what compensatory angle north of east should a drone, that can only move forward at a maximum speed of 20 m/s, be launched if it is to strike a target that is 400m due east if there is a wind moving 5 m/s south?
Homework Equations
vx=20cos[tex]\Theta[/tex]
vy=20sin[tex]\Theta[/tex]
vf2=vi2+2ad (I think?)
The Attempt at a Solution
I'm not sure how to start trying to solve this, I drew a small diagram labeled with north south east and west and it shows the object's trajectory over the 400 m. I set up a chart of known and unknown variables
x
d=400 m
a=0 m/s2
t= ?
vi=20cos[tex]\Theta[/tex]
vf=20cos[tex]\Theta[/tex]
vavg=20cos[tex]\Theta[/tex]
y
d=?
a=9.8 m/s2
t=?
vi=20sin[tex]\Theta[/tex]
vf=?
vavg=?that's all I can get