Projectile problem: throwing something off a tower

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SUMMARY

The discussion focuses on calculating the trajectory of a water balloon thrown from a height of 50 meters at an angle of 30 degrees with an initial velocity of 3 m/s. The vertical and horizontal components of the velocity were determined to be 2.6 m/s and 1.5 m/s, respectively. The time intervals for key points in the projectile's path were calculated as A (0 sec), B (0.27 sec), C (0.42 sec), and D (2.16 sec). To find the range and velocity angle, participants emphasized using the horizontal velocity and flight time.

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Homework Statement



Tossing a water balloon from a building at an angle of 30 degrees. Inital velocity is 3 m/s and the window which the balloon is thrown is 50 m from the ground.
for vertical velocity i got 2.6m/s, horizontal i got 1.5 m/s

There are 4 pts. A is the starting point. B is the middle of the projectile. C is where it is decreasing but also same horizontally as A. D is the very bottom of the projectile.

I.e. of how picture looks : http://tinypic.com/r/17srp0/6


Homework Equations





The Attempt at a Solution


So i figured out the times:
A 0 sec
B .27 sec
C .42 sec
D 2.16 sec

Now how do i get the range? and velocity angle? please help, are the values i got above correct?
 
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Hi sunshine, welcome to PF.
Show how you got those times, please. I do not understand where the points B and C are. What is "middle of projectile"? And what is same horizontally as A?


ehild
 
sunshine1228 said:
Now how do i get the range?

You know the horizontal velocity and the flight time.
 

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