Projectile question about rifles

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When a rifle is fired horizontally, the bullet strikes a screen 5.0 mm below the target at a range of 25 m. With the screen moved to 50 m, the question is how far below the target the bullet will strike again, assuming no air resistance. The time taken for the bullet to fall 5 mm can be calculated using basic physics equations. The time ratio for the bullet traveling 25 m versus 50 m is also relevant to determine the new impact point. Understanding these principles will help solve the problem effectively.
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Homework Statement



When a rifle is fired horizontally at a target P on a screen at a range of 25 m, the bullet strikes the screen at a point 5.0 mm below P. The screen is now moved to a distance of 50 m and the rifle again fired horizontally at P in its new position.

Assuming that air resistance may be neglected, what is the new distance below P at which the screen would now be struck?

Homework Equations



Horizontal Range = (u^2sin(2w))/g

All the rest simple equations.


The Attempt at a Solution



I seriously cannot do this question, I would put my attempt if I could.



Also, if someone could help me out with this. In a velocity selector, is a particle traveling in y-direction having acceleration? And is the x-component of the velocity constant?

Thanks!
 
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csharsha said:

Homework Statement



When a rifle is fired horizontally at a target P on a screen at a range of 25 m, the bullet strikes the screen at a point 5.0 mm below P. The screen is now moved to a distance of 50 m and the rifle again fired horizontally at P in its new position.

Assuming that air resistance may be neglected, what is the new distance below P at which the screen would now be struck?

Homework Equations



Horizontal Range = (u^2sin(2w))/g

All the rest simple equations.


The Attempt at a Solution



I seriously cannot do this question, I would put my attempt if I could.



Also, if someone could help me out with this. In a velocity selector, is a particle traveling in y-direction having acceleration? And is the x-component of the velocity constant?

Thanks!

If you drop the bullet out of your hand, how long does it take to fall 5mm?

What is the ratio of the time it takes the rifle bullet to travel 25m versus 50m?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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