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## Homework Statement

Your teacher tosses a basketball. The ball gets through the hoop. How long does it take the ball to reach its maximum height? How long does it take the ball to reach the hoop? What is the horizontal length of the shot? (Neglect air friction).

Initial velocity: 17 m/s

53 degree angle between the ball's initial position and the ground.

The height of the teacher is 2.576 m. (This is the ball's initial height.)

The height of the goal is 3.048 m. (This is the ball's final height.)

## Homework Equations

Vf = Vyo + at

Vyo = VoSinΘ

## The Attempt at a Solution

I solved the first part as follows:

Vyo = VoSinΘ

Vf = Vyo + at

0 = 13.5768 - 9.8t

-13.5768 = -9.8t

t = 1.3854s (Time to get to maximum height. This answer is correct.)

I'm having some trouble with the second and third part though. For the second part:

Vyo = VoSinΘ

d = Vyot + 1/2at^2

I subtracted the two heights (3.048m - 2.576m = 0.472m).

0.472m = 13.5768t + 1/2(9.8m/s^2)t^2

I then used the quadratic formula:

-13.5768 +- (square root of: ((13.5768^2) - 4(4.9)(-0.472))/(2)/(-0.472)

The answer I derived was not correct (28.4).

For the third part:

Xmax = 2Vo^2sinΘcosΘ/g

2(17^2)(sin53)(cos53)/9.8

The answer I derived was not correct (28.3).

Please help me if you can!