1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Finding Time of Flight/Maximum Height/Horizontal Range

  1. Sep 24, 2012 #1
    1. The problem statement, all variables and given/known data
    Find Time of Flight/Maximum height & horizontal range given Launch Angle and Initial Velocity.

    Using Launch angles: 9, 27, 45, 63 & 81.
    Initial Velocity: 25 m/s

    2. Relevant equations

    3. The attempt at a solution
    I used sine/cosine to find the Horizontal Range & Maximum height.

    For launch angle 9°:
    Maximum Height: 25sin9 =
    Horizontal Range: 25cos9 =

    I don't know if It's correct, also, I do not know how to find the Time of flight.

    Please help.

  2. jcsd
  3. Sep 24, 2012 #2

    Simon Bridge

    User Avatar
    Science Advisor
    Homework Helper

    That would not be correct.
    if the launch angle were 9deg, then 25sin(9) would be the y-component of the velocity.

    You need to divide the initial velocity into x and y components.
    Since the launch angle varies, you just leave it as ##\theta##.

    From there - use kinematics to write out the maximum height and range equations in terms of the acceleration (you know this) in each direction and the velocity components.
    You'll have to include an extra time of flight (T) term which you eliminate to get the final relations.

    It is an important discipline in physics to be able to write down equations without knowing what parts of them are.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook