Projectile Height Calculation: Baseball Thrown at 30 Degrees

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SUMMARY

The discussion centers on calculating the maximum height of a baseball thrown at an initial velocity of 20 m/s at a 30-degree angle from a height of 2 meters. The correct approach involves using the kinematic equation 0 = Vi^2 + 2ad, where Vi is the initial vertical velocity component. The calculated height without considering the release height is 5.0 meters, but adding the initial height of 2 meters results in a total height of 7.0 meters. Participants noted variations in gravitational acceleration (g = 9.81 m/s² vs. g = 10 m/s²) affecting the final calculations.

PREREQUISITES
  • Kinematic equations for projectile motion
  • Understanding of vector components in physics
  • Basic knowledge of gravitational acceleration (g = 9.81 m/s²)
  • Trigonometric functions for angle calculations
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  • Study the derivation and application of kinematic equations in projectile motion
  • Learn how to resolve vectors into their components using trigonometric functions
  • Explore the effects of varying gravitational acceleration on projectile calculations
  • Practice similar problems involving projectile motion with different initial heights
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bionut
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Homework Statement



A baseball is thrown with an initial velocity of 20 ms at an angle of 30 degrees with the horizontal. How high did it go if it was released and caught 2 meters from the ground?


Homework Equations





The Attempt at a Solution



0=Vi^2 + 2ad
0=(20Sin30)2 + 2 X (-9.8)d
19.62d=100
d=100/19.62
d=5.0m, but this is wrong... Would I mabey need to add 2m to my answer beacuse it is projected from a 2m height? therefore it will go 7m??
 
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bionut said:

Homework Statement



A baseball is thrown with an initial velocity of 20 ms at an angle of 30 degrees with the horizontal. How high did it go if it was released and caught 2 meters from the ground?


Homework Equations


The Attempt at a Solution



0=Vi^2 + 2ad
0=(20Sin30)2 + 2 X (-9.8)d
19.62d=100
d=100/19.62
d=5.0m, but this is wrong... Would I mabey need to add 2m to my answer beacuse it is projected from a 2m height? therefore it will go 7m??

Adding the 2 would be a very good idea , yes

EDIT: you did round off quite a bit to get 5.0m too. That is the answer you get if you take g = 10
 
I know... I got 5.10m, whihc would give 7.1m... I think my teacher sometimes uses 10 or 9.81 depends what kind of day it is ;-), lol
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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