How High Does a Jumper Raise Their Center of Gravity?

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Homework Help Overview

The problem involves a jumper taking off at a specific velocity and angle, and participants are discussing how to determine the height to which the jumper raises their center of gravity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to calculate the vertical and horizontal components of the jumper's velocity and are questioning the application of projectile motion equations. There is discussion about whether to treat the jumper's center of gravity as a vertical launch and whether the angle should be interpreted differently.

Discussion Status

Some participants are exploring different interpretations of the problem, particularly regarding the angle of takeoff. There is a recognition of potential errors in the calculations, and guidance has been offered regarding the interpretation of the angle, but no consensus has been reached on the correct approach or final answer.

Contextual Notes

Participants are considering the implications of treating the jumper's center of gravity differently and are questioning the accuracy of their calculations based on the given angle.

bionut
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Homework Statement


A jumper takes off with a velocity of 5 ms at an angle of 20 degrees to the horizontal.
How high does he raise his center of gravity?



Homework Equations





The Attempt at a Solution


I know that Vh= 5scos20 = 1.7 m/s and Vv=5Csin20=4.70 m/s

using 0=Vi^2 + 2ad
0=5sin20 + 2 X-9.81d
19.62d=1.7
d=1.7/19.62
d=0.087m, but its incorrect. Am I misssing something? The only Thing I can think of is beacuse its his centre of gravity that I should treat it as a vertical launnched projectile?
 
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bionut said:

Homework Statement


A jumper takes off with a velocity of 5 ms at an angle of 20 degrees to the horizontal.
How high does he raise his center of gravity?



Homework Equations





The Attempt at a Solution


I know that Vh= 5sin20 = 1.7 m/s and Vv=5Cos20=4.70 m/s

using 0=Vi^2 + 2ad
0=5sin20 + 2 X-9.81d
19.62d=1.7
d=1.7/19.62
d=0.087m, but its incorrect. Am I misssing something? The only Thing I can think of is beacuse its his centre of gravity that I should treat it as a vertical launnched projectile?

Nothing wrong with your calculation. Since they are asking how high, could this be the high-jump and the angle is actually 20 degrees to the vertical?
 
thanks for your help, that's what i was thinking would it then mean that the Vv is 5Cos20 instead of 5Sin20? Is that what you are suggesting?, also the answer is 0.14m...
 
Can anyone else help... I still can't get 0.14m?

:-(
 

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