Proof Help: Directional Derivatives

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Homework Help Overview

The discussion revolves around proving that a specific equation involving directional derivatives of a nonlinear function is not universally true. The equation in question relates the change in the function at a point and a vector to the directional derivative at that point.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the idea of finding counterexamples to demonstrate the falsity of the equation. Some suggest using simple nonlinear functions and specific vectors to illustrate the point. Others emphasize the need to show the statement does not hold for all nonlinear functions, not just one.

Discussion Status

The discussion is active, with participants providing different perspectives on how to approach the proof. Some offer guidance on finding counterexamples, while others clarify the requirements of the proof, indicating that a single counterexample is insufficient to disprove the statement universally.

Contextual Notes

There is an emphasis on understanding the implications of nonlinearity in functions and how it relates to the proof. Participants are also navigating the distinction between proving a statement false for all cases versus for specific instances.

rman144
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Prove the following is not true:

Let f : R^2->R^2 be a nonlinear function. For any vectors a,v in R^2;

f(a+v)-f(a)=[Df(a)]v


In terms of my attempt, I've been trying to find some combination of a and v that ensure this fails, but so far the best I've come up with is to start with:

[Df(a)]v=lim{h->0} (f(a+hv)-f(a))/h

And then trying to show that f(a+v)-f(a) is the same thing only as h->1; again, no luck. I really just need a hint or two as to which way to approach the proof.
 
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To show an equation is false you don't have to prove a big theorem. You just have to find an example where it doesn't work. Have you actually tried any examples? Take something simple with a squared term, an easy point and an easy unit vector. Almost anything you try should give a counterexample. Just show the equation you are given doesn't work using the formula for directional derivative.
 
Read the text; finding a counter example for one function f simply proves that it doesn't hold for that ONE function f; the problem asks to show this is true for ANY nonlinear function.
 
rman144 said:
Read the text; finding a counter example for one function f simply proves that it doesn't hold for that ONE function f; the problem asks to show this is true for ANY nonlinear function.

Read the text yourself. It asks you to prove a theorem is not true.
 
You can use that f is non-linear. What does that mean? Either
1) There exist x, y so that f(x+y) is NOT f(x)+f(y)

2) There exists x, c a constant so that f(cx) is NOT cf(x).

Cleverly pick your point a to be one at which f is 'not linear' so to speak (i.e. you can use a to demonstrate f is non-linear by one of these).
 
rman144 said:
Read the text; finding a counter example for one function f simply proves that it doesn't hold for that ONE function f; the problem asks to show this is true for ANY nonlinear function.
This is basic logic. You need to disprove a statement of the form "for all nonlinear functions f and vectors a,v: ...". This means finding one particular nonlinear function f and particular vectors a and v such that ... does not hold, is enough.
 

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