- #1
chaotixmonjuish
- 287
- 0
If a|c and b|c with (a,b)=1, prove ab|c
The book just states that ab|c if (a,b)=1...so I took a stab on proving it:
(a,b)=1 means au+bv=1
so for no reason at all I threw in a c
acu+bcv=c
since a|c and b|c c=ak and c= bh
abhu+bakv=c
this means ab(hu+kv)=c
hence ab|c
It this proof right...the book kind of skips proving this proposition.
The book just states that ab|c if (a,b)=1...so I took a stab on proving it:
(a,b)=1 means au+bv=1
so for no reason at all I threw in a c
acu+bcv=c
since a|c and b|c c=ak and c= bh
abhu+bakv=c
this means ab(hu+kv)=c
hence ab|c
It this proof right...the book kind of skips proving this proposition.