1. The problem statement, all variables and given/known data Let u, and v be vectors in Rn, and let c be a scalar. c(u+v)=cu+cv 3. The attempt at a solution Proof: Let u, v ERn, that is u=(ui)ni=1, and v=(vi)ni=1. Therefore c(ui+vi)ni=1 At this point can I distribute the "c" into the parenthesis? For example: =(cui+cvi)ni=1 =(cui)ni=1+(cvi)ni=1 =cu+cv.