- #1

Crution

- 10

- 0

## Homework Statement

Let A be a square matrix such that I-A is nonsingular.

Prove that A * (I-a)^-1 = (I-A)^-1 * A

## Homework Equations

Now I think that

A^-1 * A = A*A^-1 = I

and

I*A = A*I

are relevant for this.

## The Attempt at a Solution

I tried to express (I-a)^-1 in respect to I without having an inversion in it. but somehow I can't get it to work.

Any ideas?