Proofs of Basic Linear Algebra Concepts - A Guide for Beginners

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The discussion focuses on verifying proofs related to basic linear algebra concepts. The first proof demonstrates that in any vector space V, the equation (a+b)(x+y) = ax + ay + bx + by holds true, with suggestions for simplification and clarity. The second proof aims to show that a linear combination of vectors from a subspace W remains in W, with recommendations to use mathematical induction for rigor. Participants provide feedback on improving the clarity and correctness of the proofs, emphasizing the importance of following vector space axioms. Overall, the thread serves as a collaborative effort to refine understanding and presentation of foundational linear algebra proofs.
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Hello. I've been reading through Friebderg's Linear Algebra and doing some of the problem sets. I can do the problems with little problem, but I want to make sure my proofs are okay looking. These are pretty basic though. I'm pretty sure I got the first one, just want to make sure that's right. The second one I need a bit of suggetsions on.

Thank you : )

1: In any vector space V, show that (a+b)(x+y) = ax + ay + bx + by, where x,y \in V and a,b \in R (a, b scalars.)

Proof:
Let c = a+b

c(x+y) = cx + cy By Axiom 7 that states "a(x+y) = ax + ay, scalar a, and x,y, in V".

Next, I said c = a+b, so by another Axiom that states (a+b)x = ax + bx

(a+b)x + (a+b)y = ax + bx + ay + by
That should complete the proof. I think that's right.

Next one is one I'm not too sure if myproof is correct/clear. Any comments/suggestions would be appreciated.

2: If W is a subspace of V and x_1, x_2, ...x_n \in W Prove that a_1 x_1 + a_2 x_2 ... a_n x_n \in W (a_n is a scalar real number.)

Proof:

By a theorem earlier in the chapter, I first noted that for W to be a vector space V, then

A:x +y \in W | x,y \in W
and
B:ax \in W whenever a is a scalar and x \in W

So, here was how my poorly constructed argument went.

I already know that W is a subspace of V, I just want to show that linear combination above is also in W.

Let me arbitrarily choose a vector in that linear combination, I'll denote it a_i x_i, 1 <= i <= n. I know that this must be in W, as that is stated by B in the previous theorem mentioned.

So, we know that each of those a_i x_i in the linear combination themselves are vectors in W. This gets me a step closer to showing the sum itself is.

Now, Let me denote any a_i x_i = y. Now, I know that y_1 + y_2 \in W as that is stated by the part A of the previously mentioned theorem. So, I can now say that the sum of any two of the a_i x_i in that linear combination is in W. Now, If I know that the sum of two of those is in W, I can consider that a new element of W called Z then add another a_i x_i. This will also be in W, as it is the sum of two vectors already in W. It is clear that continuing this adding process of the elemnts of W is producing elements within W. So, I can continue this repetively until all the elements in that linear combination are summed and I have a vector X which is in the element W that is that linear combination.

This sounds rather wordy, and I'm concerned that it isn't rigorous enough. Anyone have any ideas? Does my argument even work? Thanks!
 
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The first proof looks good. Two suggestions. First, you don't need all those intermediate variables. For example, instead of defining c=a+b and saying c(x+y)=cx+cy, just treat a+b as a scalar (which it is), so that you can say (a+b)(x+y) = (a+b)x+(a+b)y. You do this a few other places as well. Second, to make the second part more rigorous, you should use induction. That is, assume the sum of the first k elements belongs to W and show this means the sum of the first k+1 belong to W as well. Then show the initial case and you'll be done.
 
Thank you for the reply. I like the idea of trying it by induction. I'll give htat a shot. I'll work on it. If I make any progress, I'll post it. Thanks for the suggestion : )
 
You're first proof is incorrect, but you had the right idea. I'll quote the vector space axioms straight from the text for you(from the 4th edition).

Here's a proof.

Suppose we have some vectors x, y in V and scalars a, b in R, then
(a + b)(x + y) = (a + b)x + (a + b)y by (VS 7)
= (ax + bx) + (ay + by) by (VS 8)
= ax + (bx +(ay + by)) by (VS 2)
= ax + ((bx + ay) + by) by (VS 2)
= ax + ((ay + bx) + by) by (VS 1)
= ax + ay + bx + by.
Since x, y in V and a, b in R were arbitrary, this holds for all x, y in V and all a, b in R.

Try to follow this, the only tricky part might be where (VS 2) is used. Also the question in my text says any field F(maybe a different edition). Hope that helps.

Edit yet again: Another problem(if you have the 4th edition) that is similar to this one in the sense you are proving really basic properties about vector spaces, is #9 where it asks you to prove Corollaries 1 and 2 of Theorem 1.1 and Theorem 1.2(c). This is good practice.
 
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