Proton Motion in Electric Field

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SUMMARY

The discussion centers on calculating the kinetic energy (KE) and velocity of a proton moving in an electric field created by two metal sheets with a potential difference of 40 volts. The kinetic energy is determined using the formula KE = qV, resulting in a value of 6.4 x 10-18 joules. The calculated velocity of the proton just before it strikes the negatively charged sheet is confirmed to be 87548 m/s, validating the kinetic energy calculation.

PREREQUISITES
  • Understanding of electric fields and potential difference
  • Familiarity with kinetic energy formulas (KE = qV and KE = mv2/2)
  • Basic knowledge of particle physics, specifically protons
  • Ability to perform calculations involving scientific notation
NEXT STEPS
  • Study the relationship between electric fields and force on charged particles
  • Learn about energy conservation in electric fields
  • Explore advanced topics in electromagnetism, such as electric potential energy
  • Investigate the behavior of particles in vacuum conditions
USEFUL FOR

Students in physics, particularly those studying electromagnetism, as well as educators and anyone interested in the dynamics of charged particles in electric fields.

XTEND
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Homework Statement


2 large metal sheets are separated by a potential of 40 volts by a vaccum. When the proton particle (mass 1.67x10e-27 kg)is released close to the (+) sheet it moves closer to the (-) sheet by way of electric field. What's the KE right before the proton smacks the other sheet? And what's the velocity of before striking the (-) sheet?


Homework Equations



KE=>q*v and EK=mv^2/2

The Attempt at a Solution



KE= 1.6x10e-19(40)=6.4x10e-18

v= ?
 
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What's the formula for the kinetic energy of an object (in terms of the object's velocity)?
 
Can anyone help me with this?

I think the velocity is 87548 m/s. Is this correct?
 
XTEND said:
Can anyone help me with this?

I think the velocity is 87548 m/s. Is this correct?

Your answer is correct.
 
what about the first part for KE?
 
XTEND said:
what about the first part for KE?

If that isn't correct, you wouldn't have gotten the right answer for v. So yes, KE=qV, and your calculation is right as well.
 

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