Proton + Proton = Deuterium? How?

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The discussion centers on the fusion process where two protons collide to form Deuterium, highlighting the role of Beta minus decay in this reaction. It is established that during the collision, one proton undergoes transmutation, emitting a positron and an electron-associated neutrino through a weak interaction. The conversation also notes that the proton-proton fusion process is distinct from the deuterium-deuterium reaction, which requires a photon, indicating the electromagnetic nature of the latter compared to the weak interaction of proton fusion.

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In this Picture: http://upload.wikimedia.org/wikipedia/commons/7/78/FusionintheSun.svg at the beginning, two protons collide and create a Deuterium.
But from the other left-over's we can see that a Beta minus decay has occurred to one of the protons.
So it means that one proton decayed and then collided with the proton?
Or the collision made the proton decay?
 
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Smarky said:
In this Picture: http://upload.wikimedia.org/wikipedia/commons/7/78/FusionintheSun.svg at the beginning, two protons collide and create a Deuterium.
But from the other left-over's we can see that a Beta minus decay has occurred to one of the protons.
So it means that one proton decayed and then collided with the proton?
Or the collision made the proton decay?
The proton transmutation is considered to happen at the time of collision. It's a positron emission with an electron associated neutrion that is emitted via a weak process.

http://hyperphysics.phy-astr.gsu.edu/Hbase/astro/procyc.html#c4
 
My guess is that those pictures are meant to show why the strong tritium reaction is the dominant one. The d+d reaction requires a photon, so it is EM. The p+p requires a neutrino, so it is weak.
 

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