Prove A Orthogonal $\Rightarrow$ |A|=+-1

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For an orthogonal matrix A, it is established that the determinant |A| equals ±1. This conclusion arises from the property that the inverse of an orthogonal matrix is its transpose, expressed as A-1 = AT. The proof involves the identity I = AAT, leading to the equation |I| = |AAT|, which simplifies to 1 = |A| * |AT|. Since |A| = |AT|, it follows that |A|² = 1, confirming that |A| must be ±1.

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eyehategod
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Prove if A is orthogonal matrix, then |A|=+-1
A^{-1}=A^{T}
AA^{-1}=AA^{T}
I=AA^{T}
|I|=|AA^{T}|
1=|A|*|A^{T}|//getting to the next step is where i get confused. Why is |A|=|A^{T}|
1=|A|*|A|
1=|A|^{2}
+-1=|A|
 
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I think there is an error in your question. For matrices to be orthogonal A_inverse= A_transpose.

Sorry I am not yet familiar with LATEX.
 
eyehategod said:
getting to the next step is where i get confused. Why is |A|=|A^{T}|
This is a standard result. You should probably find it in your textbook, or try to prove it yourself.
 

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