Prove Au and Av Linearly Independent

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SUMMARY

The discussion centers on proving that if \( u_1, \ldots, u_n \) are linearly independent column vectors in \( \mathbb{R}^n \) and \( A \) is an invertible \( n \times n \) matrix, then the transformed vectors \( Au_1, \ldots, Au_n \) remain linearly independent. The proof leverages the definition of linear independence and the properties of invertible matrices, emphasizing that the result does not hold if \( A \) is not invertible. The relevance of column spaces, row spaces, and null spaces is also highlighted as a potential avenue for deeper understanding.

PREREQUISITES
  • Understanding of linear independence in vector spaces
  • Knowledge of properties of invertible matrices
  • Familiarity with column spaces and row spaces
  • Basic concepts of null spaces in linear algebra
NEXT STEPS
  • Study the properties of invertible matrices in linear algebra
  • Learn about the relationship between column spaces and linear independence
  • Explore the implications of null spaces on vector transformations
  • Investigate examples of linear independence in higher dimensions
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Students and educators in linear algebra, mathematicians exploring vector space theory, and anyone interested in the implications of matrix transformations on linear independence.

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Homework Statement


Let u_1...u_n be linearly independent column vectors in R^n and A an invertible n x n matrix. Prove that the vectors Au_1...Au_n are linearly independent.


Homework Equations





The Attempt at a Solution



It is easy to prove this using scalars and the definition of linear independence. But, then why is this relevant to invertible matrices? Is there a way to prove this using column spaces, row spaces, null spaces, etc?
 
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It is not true if A is not invertible!
 

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