Prove Cauchy sequence & find bounds on limit

Click For Summary
The discussion focuses on proving that the sequence x_1, x_2, x_3,... is a Cauchy sequence under the condition |x_k - x_{k-1}| < 10^{-k} for k ≥ 2. The triangle inequality is applied to show that the difference |a_n - a_m| can be bounded by a series of terms involving powers of ten, leading to the conclusion that |a_n - a_m| can be made arbitrarily small. This suggests that the sequence converges, thus satisfying the Cauchy criterion. The next step involves determining the bounds on the limit of the sequence, with x_1 given as 2. The discussion indicates that further mathematical insight is needed to finalize the proof and establish these bounds.
*melinda*
Messages
86
Reaction score
0
Here's the problem statement:

Prove that x_1,x_2,x_3,... is a Cauchy sequence if it has the property that |x_k-x_{k-1}|&lt;10^{-k} for all k=2,3,4,.... If x_1=2, what are the bounds on the limit of the sequence?

Someone suggested that I use the triangle inequality as follows:

let n=m+l
|a_n-a_m|=|a_{m+l}-a_m|
|a_{m+l}-a_m|\leq |a_{m+l}-a_{m+l-1}|+|a_{m+l-1}-a_{m+l-2}|+...+|a_{m+1}-a_m|

Now by hypothesis, |a_k-a_{k-1}|&lt;10^{-k}, so

|a_{m+l}-a_m|&lt;10^{-(m+l)}+10^{-(m+l-1)}+...+10^{-(m+1)}.

It looks like we have an \epsilon such that |a_n-a_m|&lt;\epsilon. Before we get to the bounds on the limit, is that correct? Is anything missing?
 
Physics news on Phys.org
You might take it a little further:

|a_{m+l}-a_m|&lt;\sum_{i=0}^l 10^{m+l-i}

|a_n-a_m|&lt;\sum_{i=0}^{n-m} 10^{n-i}

I'll let a real mathematician help you the rest of the way.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
11
Views
2K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K