Prove Sequence: Limit an=Limit an+1

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SUMMARY

The discussion centers on proving that the limit of the nth term of a sequence, denoted as a_n, is equal to the limit of the (n+1)th term, a_{n+1}. The key equation utilized is the definition of the limit: \lim_{n \to \infty} a_n = L if for any \epsilon > 0, there exists an N = N_\epsilon such that |a_n - L| < \epsilon for all n > N. The proof requires demonstrating that if a_n converges to L, then a_{n+1} must also converge to L.

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Homework Statement



I have no idea
I wish If someone can help me with proving that the limit of nth term of a seq. an = to the limit of an+1

Homework Equations



we might use that an is greater of smaller than the other term which is an+1

The Attempt at a Solution


we might suppose any sequn. ??
 
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You could use the definition of limit.

\lim_{n \to \infty} a_n = L
iff for any \epsilon &gt; 0 there exists an N = N_\epsilon such that |a_n - L| &lt; \epsilon whenever n > N.

Now suppose that
\lim_{n \to \infty} a_n = L
and let \epsilon &gt; 0.
Can you now prove that
\lim_{n \to \infty} a_{n + 1} = L
?
 

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