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## Homework Statement

Prove that sinh(kt) is of exponential order |k|.

Find M>0, c>=0 and T>0 to show that

|f(t)|= Me^(ct), t>T

## Homework Equations

|f(t)|= Me^(ct), t>T

## The Attempt at a Solution

I'm looking at the graph of sinhkt (i graphed a few values of k) and indeed it is of an exponential order.

Now,

|sinhkt|<=Me^(ct), t>T

sinhkt isnt bound. So c=/=0=/=t

oh boy... help?