Prove that the equation is satisfied at least once

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The discussion centers on proving the existence of natural numbers abcdwxyz, all greater than or equal to 2015, that satisfy the equation f(x) + f(y) + f(z) + f(w) = f(a) + f(b) + f(c) + f(d), where abcd and wxyz are distinct. The function f(n) is defined as the smallest integer greater than n^pi. Participants suggest using the well-ordering principle and induction as potential methods for proof. The attempt at a solution involves expressing f(x) in terms of x and identifying the smallest x that meets the equation, but the contributor expresses uncertainty about the next steps. The pigeonhole principle is also mentioned as a possible tool to aid in the proof.
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Homework Statement


f(n) is function that takes input n and outputs the smallest integer grater that n^pi
prove that there exists natural numbers abcdwxyz that are all not smaller than 2015 such that equation is satisfied
f(x) + f(y) + f(z) + f(w) = f(a) + f(b) + f(c) + f(d)
and they abcd and wxyz are not trivial meaning that a,b,c,d is not equal to w,x,y,z

Homework Equations



well ordering principal
or maybe induction

The Attempt at a Solution


f(x) + f(y) + f(z) + f(w) = f(a) + f(b) + f(c) + f(d)
f(x) = [x^pi + 1]
f(y) = [y^pi + 1]
and so on
[x] means greatest number smaller than x for example [32.23] = 32 [12.99] = 12
let x0 be the smallest x that satisfies the equation
and i am stuck i don't know what to do afterwards
 
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The pigeonhole principle can help here.
 
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