Prove that the square root of 3 is not rational

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SUMMARY

The square root of 3 is proven to be irrational through a contradiction method. The argument establishes that if √3 were rational, it could be expressed as a fraction p/q, where p and q are integers and q is not zero. However, upon assuming this and manipulating the equation, it leads to a conclusion that contradicts the initial assumption, confirming that √3 cannot be expressed as a ratio of integers.

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  • Understanding of rational and irrational numbers
  • Familiarity with proof by contradiction
  • Basic knowledge of algebraic manipulation
  • Concept of integers and their properties
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  • Study the proof of the irrationality of √2 for comparative analysis
  • Explore the properties of rational and irrational numbers in depth
  • Learn about different proof techniques in mathematics, such as direct proof and proof by contrapositive
  • Investigate the implications of irrational numbers in real-world applications
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Homework Statement


Show that the square root of 3 is not rational


Homework Equations





The Attempt at a Solution



A number is irrational if χ is not ε. Q=p/q: p, q ε z and q is not=0, z=integers

If p/q: p, q is not ε or q=0, then square 3 is rational. If p=square root of 3 and q is not ε, then the square root of 3 cannot be rational.

Could someone please tell me if this is correct and if not show me what I need to do?

Thank you very much
 
Physics news on Phys.org
What is your \epsilon?
Do you know how to show that \sqrt{2} is irrational?
 
x ε is "x is an element of x" Yes, I do.

Thank you very much

Now I know how to do it

Regards
 

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