- #1

lahanadar

- 22

- 2

^{jωt}. To find period of the signal I tested if x(t)=x(t+nT) for all n:

e

^{jωt}=e^{jω(t+nT)}⇒ e^{jωnT}=1=e^{j2πk}where n and k are integers. Then I find a general period expression as

T=2πk/ωn

Period T means it is the least time a signal repeat itself. As an example, pick k=1, n=1, then T

_{1}=2π/ω. Now pick k=3, n=2, then T

_{2}=3π/ω. These two periods seem valid for the same signal x(t) in contrary it shouldn't, since a signal should have only one period. Am I missing something here?