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Period of a complex exponential signal

  1. Dec 5, 2016 #1
    I have a simple complex exponential signal of the form x(t)=ejωt. To find period of the signal I tested if x(t)=x(t+nT) for all n:

    ejωt=ejω(t+nT) ⇒ ejωnT=1=ej2πk

    where n and k are integers. Then I find a general period expression as

    T=2πk/ωn​

    Period T means it is the least time a signal repeat itself. As an example, pick k=1, n=1, then T1=2π/ω. Now pick k=3, n=2, then T2=3π/ω. These two periods seem valid for the same signal x(t) in contrary it shouldn't, since a signal should have only one period. Am I missing something here?
     
  2. jcsd
  3. Dec 5, 2016 #2

    mfb

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    Staff: Mentor

    If x(t)=x(t+nT) for all n, then x(t)=x(t+nT)=x(t+n(2T)) for all n by using the same step twice. If T is a period, then 2T is a period as well, and 3T and so on. Usually, just the smallest value is called period of a signal.
     
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