Prove this inequality using induction

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SUMMARY

The discussion focuses on proving an inequality using mathematical induction, specifically addressing the case where the base case is established for n=1 with the condition x ≤ 1/3. The inductive step involves combining the last two numbers and applying the base case to demonstrate that (1-x1)(1-x2) ≥ 2/3 holds true for n=2. The hint provided clarifies the process of reducing the problem from n+1 to n numbers, which is crucial for generalizing the proof.

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Homework Statement
Given n positive numbers x1, x2, . . . , xn such that x1 + x2 + · · · + xn <= 1/3, prove by
induction that
(1 − x1)(1 − x2) × · · · × (1 − xn) >= 2/3
Relevant Equations
Principle of Induction, proof by induction, base case, inductive step
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Been stuck on this one for a while now.

Base case is easy, n=1, we have x <=1/3, so trivially 1-x>= 2/3 and we are done.

The issue is with the inductive step, I don't know how to use the hint, infact I am struggling to understand what is meant by the hint.

Any help (or a full solution) would be greatly appreciated.
 
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sdfsfasdfasf said:
The issue is with the inductive step, I don't know how to use the hint, infact I am struggling to understand what is meant by the hint.
The hint means that when you have ##n + 1## numbers, you combine the last two numbers by adding them, and then you only have ##n## numbers.
 
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To make that a little more explicit: Consider ##x_1 + x_2 = y \leq 1/3##. Then by the ##n=1## case, ##(1-y) \geq 2/3##. Therefore ##(1-x_1)(1-x_2) = 1 - y + x_1 x_2 \geq 1-y \geq 2/3##, which proves the relation for ##n=2##. Now generalize this to an induction step.
 
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