Prove this inequality using induction

sdfsfasdfasf
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Homework Statement
Given n positive numbers x1, x2, . . . , xn such that x1 + x2 + · · · + xn <= 1/3, prove by
induction that
(1 − x1)(1 − x2) × · · · × (1 − xn) >= 2/3
Relevant Equations
Principle of Induction, proof by induction, base case, inductive step
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Been stuck on this one for a while now.

Base case is easy, n=1, we have x <=1/3, so trivially 1-x>= 2/3 and we are done.

The issue is with the inductive step, I don't know how to use the hint, infact I am struggling to understand what is meant by the hint.

Any help (or a full solution) would be greatly appreciated.
 
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sdfsfasdfasf said:
The issue is with the inductive step, I don't know how to use the hint, infact I am struggling to understand what is meant by the hint.
The hint means that when you have ##n + 1## numbers, you combine the last two numbers by adding them, and then you only have ##n## numbers.
 
To make that a little more explicit: Consider ##x_1 + x_2 = y \leq 1/3##. Then by the ##n=1## case, ##(1-y) \geq 2/3##. Therefore ##(1-x_1)(1-x_2) = 1 - y + x_1 x_2 \geq 1-y \geq 2/3##, which proves the relation for ##n=2##. Now generalize this to an induction step.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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