Proving a Polygon's Diagonal Formula with Induction | Step-by-Step Guide

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Homework Help Overview

The discussion revolves around proving by induction that a polygon with n angles has Mn = (n-3)n/2 diagonals. Participants are exploring the validity of the formula and the steps involved in mathematical induction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the base case for n=3 and the subsequent steps in the induction process. There are questions about the correctness of the induction hypothesis and the application of the second formula. Some participants express confusion about the steps of induction, particularly in how to show the statement holds for n+1.

Discussion Status

There is ongoing dialogue about the correctness of the approaches taken. Some participants have provided guidance on how to structure the proof, while others are questioning the assumptions made and the clarity of the steps involved. Multiple interpretations of the induction process are being explored.

Contextual Notes

Participants note difficulties with language and understanding the induction process in general. There is mention of textbook references that may influence the discussion, and some participants express uncertainty about the definitions and implications of the formulas used.

  • #31
Mark44 said:
I disagree that what needs to be done is "rearrange" Mk + D to look like Mk+1. I might be misinterpreting what you mean by "rearrange" here, but my problem with nikotin's work is that it seems like all he is doing is replacing n by n + 1 in the formula, which is not how an induction proof is proved. If that's not what he's doing, then his work needs to be clearer.
I was getting at what you were getting at: that if you know how to transform the number of diagonals for a k-gon into that for a (k+1)-gon, and if that transform maps the proposed number of diagonals for a k-gon to the proposed number of diagonals for a (k+1)-gon then the inductive hypothesis is satisfied. All that remains to be done is to confirm that the proposed number of diagonals is correct for one case.

OP: I sometimes find a counter-example helpful. I propose that the number of diagonals is much simpler: M'n=n. The inductive hypothesis would have it that if this is true for some n=k then M'k+1 (=k+1) should be equal to M'k+k-1 (=2k-1). Since this statement is not true, my idea is not consistent with the inductive hypothesis and so fails.

Try again: M''n=Mn+3. This does satisfy the inductive hypothesis (easy to verify since I've stolen the correct solution and broken it). So, if it were true for some n=k, then it would be true for all n. However, it is not true for a concrete value of n, say n=3, so fails.
 

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