Proving a Product of Commutative Rings not an Integral Domain:

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SUMMARY

The discussion centers on proving that the product of two commutative rings, denoted as R × S, cannot be classified as an integral domain. An integral domain is defined as a commutative ring with unity (1 ≠ 0) and the absence of zero-divisors. The proof is established by demonstrating that the product (1,0) × (0,1) results in (0,0), confirming the presence of zero-divisors in R × S, thereby disqualifying it as an integral domain.

PREREQUISITES
  • Understanding of commutative rings
  • Knowledge of integral domains
  • Familiarity with zero-divisors
  • Basic algebraic structures in abstract algebra
NEXT STEPS
  • Study the properties of integral domains in detail
  • Explore examples of commutative rings and their products
  • Learn about zero-divisors and their implications in ring theory
  • Investigate other algebraic structures, such as fields and modules
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Students and educators in abstract algebra, mathematicians exploring ring theory, and anyone interested in the foundational concepts of algebraic structures.

silvermane
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Homework Statement


Prove that if we have two commutative rings R and S and form the product R X S, then R X S cannot be an integral domain.


The Attempt at a Solution


We have that an integral domain is a commutative ring with 1 not= 0 and with non-zero zero-divisors.

==> (1,0)X(0,1) = (0,0), Thus it's not an integral domain.

I just want to make sure I'm doing this logically correct :)
 
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I think that pretty much sums up why RXS isn't an integral domain.
 
Dick said:
I think that pretty much sums up why RXS isn't an integral domain.

lol that's what I thought, just wasn't sure if i needed more!
It seems too easy... :P
 

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