Proving Angle Bisector of A and B with Vector Magnitudes

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thenewbosco
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Prove that [tex]\frac{|B|A+|A|B}{|A|+|B|}[/tex] is the bisector of the angle formed by A and B. where i have used normal text for vector and abs value bars to represent magnitude of vector.

i have no clue how to get started on this. i have tried many approaches such as constructing a triangle with a, b, and b-a, but i cannot seem to make any progress. a couple of hints on getting started would be appreciated
 
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Write two equations:

[tex]ax+by+c = 0[/tex]
[tex]cx+dy+e = 0[/tex]
 
I don't know off the top of my head (i'm not a vector geometry expert), but if you call the bisector vector C, taking [tex]A \cdot C[/tex] and [tex]B \cdot C[/tex] and knowing the cosine half angle formula should be a decent way to start
 
a couple of hints on getting started would be appreciated
You want to know that the vector you constructed (I'll call it C) is the angle bisector of A and B. Therefore, you want to know:

(1) The angle between A and B
(2) The angle between A and C
(3) The angle between B and C

don't you?
 
Suppose that A and B intersect at some point Q, and R is some point on A , and S is some point on B . Write the vector equations of the individual lines, and then of the bisector.
 
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so i wrote A=Q+tQR
and B=Q+tQS,
as my two vector equations...how can i write the bisector