Proving Congruences of Primes: Show 2^((p-1)/2) = +1 (mod p)

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SUMMARY

The discussion centers on proving the congruence relation 2^((p-1)/2) ≡ +1 (mod p) for an odd prime p. Participants clarify that the proof involves demonstrating that p divides both 2^((p-1)/2) - 1 and 2^((p-1)/2) + 1, correcting the initial misunderstanding of the logical operator from AND to OR. The proof relies on Euler's criterion for quadratic residues and Fermat's theorem, which are essential for establishing the congruence.

PREREQUISITES
  • Understanding of modular arithmetic
  • Familiarity with Fermat's Little Theorem
  • Knowledge of Euler's criterion for quadratic residues
  • Basic concepts of prime number theory
NEXT STEPS
  • Study Euler's criterion in detail
  • Review Fermat's Little Theorem and its applications
  • Explore proofs of congruences involving prime numbers
  • Investigate the properties of quadratic residues modulo p
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Mathematicians, number theorists, and students studying advanced topics in modular arithmetic and prime number theory will benefit from this discussion.

johndoe3344
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I came across this:

Show that if p denotes an odd prime, then 2^((p-1)/2) = +1 (mod p).

So basically, this is asking me to show that p|2^((p-1)/2)-1 AND p|2^((p-1)/2)+1

But I'm stuck from there. What am I missing? Could someone help me with the proof?
 
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Can you use Wilson's theorem?

johndoe3344 said:
So basically, this is asking me to show that p|2^((p-1)/2)-1 AND p|2^((p-1)/2)+1

No, replace the AND with OR.
 
The statement is called Euler's criterion for quadratic residues. The key to prove it is Fermat's theorem.
 

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