How to Prove a Group is Cyclic?

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Homework Help Overview

The discussion revolves around proving that a group is cyclic, specifically focusing on a finite group with a prime cardinality. Participants explore definitions and properties related to cyclic groups and Lagrange's theorem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss starting with the definition of a cyclic group and consider whether the group satisfies this definition. There is an exploration of the implications of Lagrange's theorem and the possible orders of elements within the group.

Discussion Status

The discussion is progressing with participants offering guidance on definitions and theorems relevant to cyclic groups. There is an acknowledgment of the properties of the group based on its prime cardinality, and participants are actively engaging with the implications of these properties.

Contextual Notes

Participants note that the group in question is finite with cardinality p, a prime integer, which influences the nature of its subgroups and the possible orders of its elements.

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Homework Statement



How do i go about proving that a group is cyclic?

Homework Equations





The Attempt at a Solution

 
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Start with the definition of a cyclic group, and see if your group satisfies it.
 
The group, G, is a finte group with cardinality p, a prime integer. How should i start off, if i need to prove it's cyclic?
 
Are you familiar with Lagrange's theorem?
 
yes, i know that the only subgroups of G are itself and the subgroup {e} which consists of the neutral element. This is because the only possibilities of the cardinalities of the subgroups are 1 or p.
 
Ok, now pick an element of the group G, say g not equal to 1. What are the possible orders of g?
 
possible orders of g are 1 or p? Since those are the only numbers that divide the prime number p.
 
It cannot be 1 because we assumed g was not equal to the identity. So the order of g must be p, and therefore G = {1 , g, g2, ... , gp-1} which is cyclic.
 
Ok, thanku very much for the help:)
 
  • #10
No problem.
 

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