- #1
Amer
- 259
- 0
Prove or disprove
[tex]F_n(x) = sin nx [/tex] is equicontinuous
I know the definition of equicontinuous at [tex]x_0[/tex] it says for all [tex]\epsilon >0 [/tex] there exist [tex]\delta>0 [/tex] such that if [tex]d ( f(x_0),f(x) ) < \epsilon [/tex] then
[tex]d(x_0 , x) < \delta [/tex]
trying if it is equicontinuous at [tex]x_0 = 0 [/tex]
Given [tex]\epsilon > 0 [/tex]
[tex]| f(x) | < \epsilon \Rightarrow |\sin n x | < \epsilon [/tex]
delta depends on epsilon and x just how i can continue
any hints or any directions
[tex]F_n(x) = sin nx [/tex] is equicontinuous
I know the definition of equicontinuous at [tex]x_0[/tex] it says for all [tex]\epsilon >0 [/tex] there exist [tex]\delta>0 [/tex] such that if [tex]d ( f(x_0),f(x) ) < \epsilon [/tex] then
[tex]d(x_0 , x) < \delta [/tex]
trying if it is equicontinuous at [tex]x_0 = 0 [/tex]
Given [tex]\epsilon > 0 [/tex]
[tex]| f(x) | < \epsilon \Rightarrow |\sin n x | < \epsilon [/tex]
delta depends on epsilon and x just how i can continue
any hints or any directions