Proving Entirety of conj(f(conj(z))) for an Entire Function f

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Homework Help Overview

The problem involves demonstrating that the function conj(f(conj(z))) is entire, given that f(z) is an entire function. The context is rooted in complex analysis, specifically focusing on properties of entire functions and the implications of the Cauchy-Riemann equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the Cauchy-Riemann equations to establish the entire nature of the function conj(f(conj(z))). There is an exploration of the implications of the continuity of partial derivatives and the transformation of variables involved in the proof.

Discussion Status

Some participants provide feedback on the clarity of the original poster's presentation, suggesting rewording for better understanding. There is an acknowledgment of the importance of specific steps in the proof, indicating that the discussion is productive and focused on refining the argument rather than reaching a conclusion.

Contextual Notes

Participants note the need for clarity in the representation of the real and imaginary parts of the function conj(f(conj(z))). There is an emphasis on ensuring that the proof is thorough and comprehensible, without identifying any gaps in reasoning.

tylerc1991
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Homework Statement



Show that if a function f(z) = u(x,y) +iv(x,y) is entire, then the function conj(f(conj(z))) is entire.

Homework Equations



(i) The Cauchy-Riemann (CR) equations hold for functions that are entire: u_x = v_y and u_y = -v_x

(ii) conj(_) is the conjugate (i.e. there is a conjugate bar over f and over z)

The Attempt at a Solution



Since f is entire, CR is satisfied:
so u_x = v_y and u_y = -v_x

this implies:
u_x = -(-v_y) and -u_y = -(-v_x)

this implies:
CR is satisfied for a function g(z) = u(x,-y) - iv(x,-y)

but g(z) = conj(f(conj(z)))

this implies:
CR is satisfied for conj(f(conj(z)))

Since f is entire, the partial derivatives are continuous

this implies:
conj(f(conj(z))) is entire.
 
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You've got the right idea. The presentation is a little confusing. Might be best if you say conj(f(conj(z))=u1(x,y)+i*v1(x,y) where u1(x,y)=u(x,-y) and v1(x,y)=(-v(x,-y)) and show u1 and v1 satisfy CR.
 
OK I can reword it. But there are no holes in the proof? Thank you very much for your help!
 
It's all there. I just have to read between the lines a bit to figure out u_x=(-(-v_y)) is important. Do rewrite with different symbols for the real and imaginary parts of conj(f(conj(z)).
 

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