Proving Equality of Supremum and Infimum for Bounded Sets

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SUMMARY

The discussion centers on proving the equality of the supremum of the set B, defined as the set of lower bounds for a bounded below set A, and the infimum of A. It is established that sup(B) = inf(A) by demonstrating that sup(B) serves as a lower bound for A and that any lower bound of A is less than or equal to sup(B). Additionally, the necessity of asserting the existence of the greatest lower bound in the Axiom of Completeness is questioned, leading to the conclusion that bounded below sets inherently possess greatest lower bounds.

PREREQUISITES
  • Understanding of supremum and infimum concepts in real analysis
  • Familiarity with the Axiom of Completeness in real numbers
  • Knowledge of DeMorgan's Laws and their application in proofs
  • Basic skills in logical reasoning and proof writing
NEXT STEPS
  • Study the Axiom of Completeness and its implications for bounded sets
  • Learn how to construct formal proofs involving supremum and infimum
  • Explore DeMorgan's Laws and their relevance in mathematical logic
  • Review examples of proving properties of bounded sets in real analysis
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Students of real analysis, mathematicians focusing on set theory, and educators teaching concepts related to bounds and completeness in mathematics.

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Homework Statement



(a) Let A be bounded below, and define B = {b\inR : b is a lower bound for A}.
Show that sup(B) = inf(A).

(b) Use (a) to explain why there is no need to assert that the greatest lower bound exists as part of the Axiom of Completeness.

(c) Propose another way to use the Axiom of Completeness to prove that sets bounded below have greatest lower bounds.

Homework Equations



We can use the Axiom of Completeness, DeMorgan's Laws, etc...

The Attempt at a Solution



I have shown that both sup(B) and inf(A) exist.
I can see, logically, why they should be equal, but I can't seem to write it down clearly.
 
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You must show two things:

1) sup(B) is a lower bound of A
2) If x is a lower bound of A, then x\leq \sup(B).

Let's start with the first. How would you show that for all a in A it holds that \sup(B)\leq a??
 

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