Proving Equivalence of Sets A and B

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Homework Help Overview

The discussion revolves around proving the equivalence of sets A and B under specific conditions, focusing on cardinality and the properties of set operations. The original poster presents two problems related to set equivalence and Cartesian products.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of equivalence in terms of cardinality and consider constructing bijections. There are discussions about the implications of set differences and the potential cases to analyze.

Discussion Status

Some participants have offered guidance on how to approach the problems, suggesting the use of definitions and exploring different cases. There is an ongoing examination of the assumptions and conditions presented in the problems, with no clear consensus yet.

Contextual Notes

One participant notes that part of the second problem may be missing, indicating a need for clarification. The original poster's attempt at a solution was not successful, leading to further inquiry into the methods used.

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Homework Statement



1. Suppose A-B is equivalent to B-A. show that A is equivalent to B.
2. if A,B and C are nonempty and A cross B is equivalent to A cross C then B is equivalent to C
Any help would be appreciated, thanks!

The Attempt at a Solution


I tried constructing a bijection, but that did not work out right. Any ideas?
 
Last edited:
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By definition, if two sets A and B are equivalent, that every element in A is also in B, and every element in B is also in A. Can you use this idea on your first problem?

For your second problem, part of it is missing.
if A,B and C are nonempty and A cross B is equivalent to A cross then B is equivalent to C
Is the question "if A,B and C are nonempty and A cross B is equivalent to A cross C, then B is equivalent to C"
 
By equivalent, I mean they have the same cardinality, not that they are equal.
 
OK, so you know there is an bijection between A - B and B - A. It seems to me there are four cases:
A \subset B
B\subset A
A = B
A \cap B = \oslash

Can you eliminate one or more of these as possibilities, and then come up with a bijection for the remaining one(s)?

Some examples might be helpful to get you thinking in the right way.

1. A = {2, 4, 6, ...}, B = {1, 2, 3, ...}
2. A = {2, 3, 4, 5, ...}, B = {1, 2, 3, 4, ...}
3. any two sets that are equal
4. A = {2, 4, 6, ... }, B = {1, 3, 5, ... }
 

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