A complete description
Prove inequality
[itex]\begin{equation}<br />
\int^\infty_0y^\frac{2(n-1)}{n}p(y)\,\mathrm{d}y\Big(\int^\infty_0y^\frac{1}{n}p(y)\,\mathrm{d}y\Big)^2>\int^\infty_0y^\frac{2}{n}p(y)\,\mathrm{d}y\Big(\int^\infty_0y^\frac{(n-1)}{n}p(y)\,\mathrm{d}y\Big)^2<br />
\nonumber<br />
\end{equation}[/itex]
[itex]p(y)>0[/itex] and [itex]\int^\infty_0p(y)\,\mathrm{d}y=1[/itex] for any y
n is an integer and [itex]n\ge2$[/itex]