Proving Inequality: [n/(n+1)]n ≤ [(n+1)/(n+2)]n+1

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Homework Help Overview

The discussion revolves around proving the inequality \(\frac{n}{n+1}^n \leq \frac{n+1}{n+2}^{n+1}\), which falls under the subject area of inequalities and mathematical induction.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using mathematical induction, starting with base cases and exploring polynomial forms. Questions arise about simplifying terms and the potential use of binomial expansion.

Discussion Status

The discussion is ongoing, with participants exploring different approaches, including polynomial induction and simplifications. Some guidance has been offered regarding the use of simpler inequalities and polynomial forms, but no consensus has been reached.

Contextual Notes

Participants note the challenge of finding a straightforward inequality to work with and the complexity introduced by exponents in their attempts.

Jamin2112
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Homework Statement



In the middle of a certain problem I am trying to prove that [n/(n+1)]n ≤ [(n+1)/(n+2)]n+1.

Homework Equations



Could use induction (show it's true for n=1, and that if it's true for n, it's also true for n+1) or just start with some simple and obviously true inequality and then mess with it until I get the desired inequality.

The Attempt at a Solution



Haven't gotten anywhere.
 
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I quickly looked from some other "simple" inequality but I didn't find one right away.

What I did find is that you can get rid of some terms then get a polynomial and use induction on it.

The induction on the polynomial is easier than the original inequality.
 
╔(σ_σ)╝ said:
I quickly looked from some other "simple" inequality but I didn't find one right away.

What I did find is that you can get rid of some terms then get a polynomial and use induction on it.

The induction on the polynomial is easier than the original inequality.

How so? Use the binomial expansion?
 
Jamin2112 said:
How so? Use the binomial expansion?
Multiplication and approximation.

BTw I still have exponents.

Basically, I arrived at a point where all I had to do was show that

(n+2)^n < (n^2 +2n +1)^(n-1)
 

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